-x^2-10x+64=0

Solution for -x^2-10x+64=0 equation:

-x^2-10x+64=0

We add all the numbers together, and all the variables

-1x^2-10x+64=0

a = -1; b = -10; c = +64;
Δ = b2-4ac
Δ = -102-4·(-1)·64
Δ = 356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{356}=\sqrt{4*89}=\sqrt{4}*\sqrt{89}=2\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{89}}{2*-1}=\frac{10-2\sqrt{89}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{89}}{2*-1}=\frac{10+2\sqrt{89}}{-2}
$